Synopsis

(Required) The value of an expression shall not be assigned to an object with a narrower essential type or of a different essential type category

Enabled by default

Yes

Severity/Certainty

Medium/Medium

Full description

The value of an expression was found assigned to an object with a narrower essential type or a different essential type category.

Coding standards

Code examples

The following code example fails the check and will give a warning:

void example(void) {
  char a = 'a';
  unsigned int b = 10;
  b = a;
}

The following code example passes the check and will not give a warning about this issue:

void example(void) {
  unsigned int a = 10;
  unsigned int b = 5;
  b = a;
}